From: Subject: Kinematics: equations of motion II Date: Wed, 29 Dec 2004 06:29:38 -0500 MIME-Version: 1.0 Content-Type: multipart/related; type="text/html"; boundary="----=_NextPart_000_00C1_01C4ED6F.C5ADC8F0" X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_00C1_01C4ED6F.C5ADC8F0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Content-Location: http://prkw.com/pmcemotB.html Kinematics: Equations of Motion II
Multiple Choice Online Test
Indicate the correct = answer by=20 clicking on the button next to the numbers 1, 2, 3 or 4. There = is only=20 one correct answer per question. After you have answered=20 all multiple choice questions compare your choices = with=20 the correct answers.

Equations of Motion II


1.) A hunter points a dart = directly at a=20 monkey sitting on a tree. However, just as the hunter fires the dart = the=20 monkey drops from the branch. The dart will ...
    1 Strike the monkey.
    2 Pass over the monkey.
    3 Pass below the monkey.
    4 More information is required to answer the=20 question.
2.) A parachutist is descending with uniform = velocity. This=20 indicates that he is experiencing =85
    1 no forces at all
    2 zero resultant force
    3 a downward resultant force
    4 an upward resultant = force
3.) A motorcycle accelerates uniformly from rest = along a=20 straight road, reaching a speed of 200 km/h after 10,0 seconds. At = what stage=20 during the motion does the bike's speedometer needle pass the 100 km/h = mark?=20
    1 halfway along the road
    2 5,0 seconds after starting
    3 some distance after the halfway mark
    4 some time before 5 = seconds
    -2. Hence with an = acceleration of 20m.s-2 it takes 5 seconds for the bike to = reach a speed of 100 km/hr.")' type=3Dbutton value=3DExplanation>
4.) Consider the following velocity-time graph of = a car=20 starting from rest in a straight line. At what time of the movement is = the=20 object the furthest from its starting point?
    3D"equations
    1 P
    2 Q
    3 R
    4 S
5.) A girl, standing on a bridge, throws a metal = sphere=20 vertically downwards as hard as she can. Which statement concerning = the=20 acceleration of the stone after it has left her hand is true? (Ignore = any=20 effects of air resistance.)
    1 The sphere's acceleration is equal to "g".
    2 The sphere's acceleration is greater than = "g".
    3 The sphere's acceleration is less than "g".
    4 The sphere's acceleration is at first greater than "g", = then=20 becomes equal to "g".
    g     and nothing but g.")' = type=3Dbutton value=3DExplanation>
6.) How far does a stone fall in 1,0 s when = dropped on=20 earth, disregarding any air resistance?
    1 1 m
    2 5 m
    3 10
    4 20
    2, time is 1 = second, hence we can use the following equation of motion:
    s =3D =BD = g t2
    s =3D =BD =B710m/s2 =B7 = 1s2
    s =3D 5m")' type=3Dbutton = value=3DExplanation>
Question 7 and 8 refer to the diagram=20 below:

A car is moving on a straight, horizontal = road at 30=20 m.s-1 in an easterly direction. The acceleration of the car for the = following=20 20 s is shown in the graph as a function of time.

3D"equations

7.) The velocity of the car is =85

    1 5 m.s-1 west
    2 25 m.s-1 west
    3 5 m.s-1 east
    4 25 m.s-1 east
    2: velocity has decreased to 10m/s. Then = acceleration with a=3D3m.s2 increases velocity to 25m/s = (10m/s + 15m/s). After 15 seconds no further change in velocity, hence = car is travelling at 25m/s east.")' type=3Dbutton value=3DExplanation>
8.) During the 20 seconds when is the car = stationary?
    1 from 0 to 10 seconds
    2 from 10 to 15 seconds
    3 from 15 to 20 seconds
    4 never
9.) Which of the following will not effect on the=20 acceleration of a falling object on planet earth?
    1 Height of the object above sea level.
    2 Distance between centre of the earth and the = object.
    3 Mass of the object.
    4 Mass of the earth.
10.) A parachutist lands on the ground at a speed of 6 m/s. = The=20 height from which a free-falling object will have to fall to reach the = same=20 speed is =85
    1 0,30 m
    2 1,80 m
    3 3,60 m
    4 60 m
    v2 =3D u2 + 2as
    36 =3D 0 + = 2=B710=B7x
    36/20 =3D 18/10 =3D 1,8
    height =3D 1,8m.")' = type=3Dbutton value=3DExplanation>
Results
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