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Subject: Electricity (multiple choice questions)
Date: Wed, 29 Dec 2004 09:54:59 -0500
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<HTML><HEAD><TITLE>Electricity III</TITLE>
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<BODY text=3D#000000 vLink=3D#800080 aLink=3D#ff0000 link=3D#0000ff =
bgColor=3Dwhite>
<BLOCKQUOTE>
<HR color=3Dblue SIZE=3D5>
  <TABLE bgColor=3D#ffff00>
    <TBODY>
    <TR>
      <TD><B>Multiple Choice Online Test</B><BR>Indicate the correct =
answer by=20
        clicking on the button next to the numbers 1, 2, 3 or 4. There =
is only=20
        one correct answer per question. After you have answered=20
        <B><U>all</U></B> multiple choice questions compare your choices =
with=20
        the correct answers. </TD></TR></TBODY></TABLE>
  <HR width=3D"100%" color=3Dred SIZE=3D3>

  <CENTER>
  <H2>Electricity III</H2></CENTER>
  <HR width=3D"100%" color=3Dred SIZE=3D3>
  <BR>
  <FORM name=3DF><!frage1><B><FONT color=3Dred>1.)</FONT> Which one of =
the circuits=20
  shown in the diagram below can be used to determine the resistance of =
R?=20
  </B><BR>
  <TABLE cellSpacing=3D0 cellPadding=3D0 border=3D0>
    <TBODY>
    <TR>
      <TD vAlign=3Dcenter>
        <UL>
          <TABLE cellSpacing=3D0 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>
                <CENTER>I</CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>
                <CENTER>II</CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ1></TD>
              <TD>
                <CENTER>III</CENTER></TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ1></TD>
              <TD>
                <CENTER>IV</CENTER></TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("The =
electric current splits up according to the resistance (low resistance =
high current and high resistance low current). If 3 A flow into the =
parallel connection 2/3 of I (2/3 of 3A =3D 2A) will pass through the =
4&Omega; resistor and 1/3 of I (1/3 of 3A =3D 1A) through the 8&Omega; =
resistor.")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD vAlign=3Dtop=20
        =
align=3Dmiddle>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs=
p;&nbsp;&nbsp;&nbsp;=20
        <IMG height=3D267 alt=3D"electricity III, diagram 1"=20
        src=3D"http://larose/quiz/pmcelecC01.gif" width=3D350 =
border=3D1>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage2><B><FONT color=3Dred>2.)</FONT> A car's starter motor =
draws a=20
  current of 100 A at 12,0 V when starting the engine. The mechanical =
power=20
  required to turn the engine is 960 W. At what rate is energy from the =
battery=20
  converted to non-mechanical forms of energy? </B>
  <UL>
    <TABLE cellSpacing=3D0 border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ2></TD>
        <TD width=3D550>240 W</TD></TR>
      <TR>
        <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD width=3D550>960 W</TD></TR>
      <TR>
        <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD width=3D550>1200 W</TD></TR>
      <TR>
        <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ2></TD>
        <TD width=3D550>1440 W</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("Since the =
total resistance is the same (2&Omega; + 8&Omega; =3D 10&Omega;) in both =
parts of the parallel connection all ammeters will show the same =
reading.")'>
 -->
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
  </UL><!&Omega;>
  <P><!frage3><B><FONT color=3Dred>3.)</FONT> In the circuit shown below =
one of=20
  the bulbs blew. The result was that all bulbs stopped glowing. Which =
bulb=20
  blew? </B>
  <UL>
    <TABLE>
      <TBODY>
      <TR>
        <TD vAlign=3Dcenter>
          <TABLE cellSpacing=3D0 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>bulb a</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD>bulb b</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ3></TD>
              <TD width=3D120>bulb c</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ3></TD>
              <TD width=3D120>bulb d</TD></TR></TBODY></TABLE></TD>
        <TD vAlign=3Dtop>
          <CENTER><IMG height=3D156 alt=3D"electricity III, diagram 2"=20
          src=3D"http://larose/quiz/pmcelecC02.gif" width=3D350 =
border=3D0>=20
          </CENTER></TD></TR></TBODY></TABLE><!-- <input type=3D"button" =
value=3D"Explanation" onclick=3D'gibfeedback("Ohm&acute;s Law: the =
current flowing through a conductor is directly proportional to the =
potential difference across it provided the temperature of the conductor =
remains constant. Or in formulae form: R =3D I/V, to keep R constant I =
and V have to increase/decrease at the same ratio.")'>
 -->
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
  </UL>
  <P><!frage4><B><FONT color=3Dred>4.)</FONT> Three resistors are =
connected to a=20
  battery as shown in the diagram. At which point in the circuit is the =
current=20
  the smallest? </B>
  <TABLE width=3D"85%">
    <TBODY>
    <TR>
      <TD>
        <UL>
          <TABLE cellSpacing=3D0 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
              <TD align=3Dmiddle>a</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
              <TD align=3Dmiddle>b</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ4></TD>
              <TD align=3Dmiddle>c</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ4></TD>
              <TD align=3Dmiddle>d</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("Unsrewing =
one of the parallel bulbs will change the total resistance of the =
circuit in a way that it goes up. Higher resistance will cause a lower =
current to flow through the circuit (option 2 and 4). How is the p.d. =
affected? Prior to unscrewing the voltmeter measured the p.d. across one =
of the bulbs connected in parallel, which had a lower resistance since =
they were in parallel (1/R<sub>total</sub> =3D 1/R<sub>1</sub> + =
1/R<sub>2</sub>). After unscrewing a higher voltage is required to drive =
the current through the bulb &raquo; voltmeter reading goes up.")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD vAlign=3Dtop align=3Dmiddle><IMG height=3D152=20
        alt=3D"electricity III, diagram 3"=20
        src=3D"http://larose/quiz/pmcelecC03.gif" width=3D380 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage5><B><FONT color=3Dred>5.)</FONT> In the circuit shown, the =
resistance=20
  of the ammeter, the battery and the connecting wires are negligible. =
The=20
  voltmeter has a very high resistance. The ammeter reads 1,5 A. What is =
the=20
  reading on the voltmeter? </B>
  <TABLE width=3D"90%" border=3D0>
    <TBODY>
    <TR>
      <TD>
        <UL>
          <TABLE border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD>4 V</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ5></TD>
              <TD>6 V</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD>8 V</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ5></TD>
              <TD>12 V</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("No current =
will flow in the circuit due to the position of the voltmeter. =
Voltmeters have a very high resistance - ammeters on the other hand have =
a very low resistance - and hence we can say that the resistance of the =
voltmeter <i>blocks somehow the current</i>. Since the voltmeter is =
connected across the terminals of the source of electricity it will =
measure the emf of the battery.")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD vAlign=3Dtop><IMG height=3D173 alt=3D"electricity III, diagram =
4"=20
        src=3D"http://larose/quiz/pmcelecC04.gif" width=3D211 =
border=3D0>=20
    </TD></TR></TBODY></TABLE><!&Omega;>
  <P><!frage6><B><FONT color=3Dred>6.)</FONT> Two resistors are =
connected in=20
  parallel as shown in the diagram. The current flowing through the =
ammeter is:=20
  </B>
  <TABLE width=3D"90%">
    <TBODY>
    <TR>
      <TD>
        <UL>
          <TABLE cellSpacing=3D0 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD>0,6 A</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD>1,5 A</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ6></TD>
              <TD>2,5 A</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ6></TD>
              <TD>14,4 A</TD></TR></TBODY></TABLE><!-- <input =
type=3D"button" value=3D"Explanation" onclick=3D'gibfeedback("Only in =
option 2 the effective resistance is 6&Omega;: 4&Omega; and 4&Omega; in =
parallel - 1/R =3D 1/4 + 1/4 =3D 1/2 hence R =3D 2&Omega;. 4&Omega; is =
in series with 2&Omega; hence R combined =3D 2&Omega; + 4&Omega; =3D =
6&Omega;.")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD><IMG height=3D172 alt=3D"electricity III, diagram 5"=20
        src=3D"http://larose/quiz/pmcelecC05.gif" width=3D210 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage7><B><FONT color=3Dred>7.)</FONT> Consider the circuit shown =
to the=20
  right. If switch S is closed, the readings on the voltmeter and =
ammeter will=20
  change as follows: </B>
  <TABLE>
    <TBODY>
    <TR>
      <TD>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50>&nbsp;</TD>
              <TD align=3Dmiddle><B>voltmeter =
reading&nbsp;&nbsp;</B></TD>
              <TD align=3Dmiddle><B>&nbsp;&nbsp;ammeter =
reading</B></TD></TR>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD align=3Dmiddle>becomes zero</TD>
              <TD align=3Dmiddle>remains the same</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ7></TD>
              <TD align=3Dmiddle>becomes zero</TD>
              <TD align=3Dmiddle>increases</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD align=3Dmiddle>remains the same</TD>
              <TD align=3Dmiddle>decreases</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ7></TD>
              <TD align=3Dmiddle>decreases</TD>
              <TD align=3Dmiddle>increases</TD></TR></TBODY></TABLE><!-- =
<input type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("B<sub>2</sub> and B<sub>3</sub> are connected in =
parallel, hence only 50% of the current will flow through each of those =
bulbs and the p.d. across them will be less than the p.d. across =
B<sub>1</sub> (1/3 of total p.d. will be across B<sub>2</sub> and =
B<sub>3</sub>; 2/3 of total p.d. across B<sub>1</sub>). As a result =
B<sub>1</sub> will shine brightest (power =3D current <small>x</small> =
voltage) and B<sub>2</sub> and B<sub>3</sub> will have the same =
brightness. ")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD>&nbsp;&nbsp;&nbsp;<IMG height=3D132 alt=3D"electricity III, =
diagram 6"=20
        src=3D"http://larose/quiz/pmcelecC06.gif" width=3D210 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P><!frage8><B><FONT color=3Dred>8.)</FONT> The circuit below shows =
two=20
  identical bulbs, L and M, which are connected to a battery and a =
variable=20
  resistor R. How will the brightness of the bulbs be affected if the =
resistance=20
  of R is increased? </B>
  <TABLE>
    <TBODY>
    <TR>
      <TD>
        <UL>
          <TABLE cellSpacing=3D0 cols=3D2 border=3D0>
            <TBODY>
            <TR>
              <TD width=3D50>&nbsp;</TD>
              <TD><B>&nbsp;&nbsp;bulb L&nbsp;&nbsp;</B></TD>
              <TD><B>&nbsp;&nbsp;bulb L&nbsp;&nbsp;</B></TD></TR>
            <TR>
              <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ8></TD>
              <TD align=3Dmiddle>dimmer</TD>
              <TD align=3Dmiddle>brighter</TD></TR>
            <TR>
              <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle>dimmer</TD>
              <TD align=3Dmiddle>dimmer</TD></TR>
            <TR>
              <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle>dimmer</TD>
              <TD align=3Dmiddle>the same</TD></TR>
            <TR>
              <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ8></TD>
              <TD align=3Dmiddle>brighter</TD>
              <TD align=3Dmiddle>the same</TD></TR></TBODY></TABLE><!-- =
<input type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("After closing the switch no current will flow =
through X, hence it will not lit up (option 4) and consequently a hgher =
current will pass through bulb Y making it shine brighter.")'>
 -->
          <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
        </UL></TD>
      <TD vAlign=3Dtop>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; =
<IMG=20
        height=3D150 alt=3D"electricity III, diagram 7"=20
        src=3D"http://larose/quiz/pmcelecC07.gif" width=3D276 =
border=3D0>=20
    </TD></TR></TBODY></TABLE>
  <P>
  <CENTER><STRONG><FONT color=3Dred>The information given in the box =
refers to=20
  questions 9 and 10:</FONT></STRONG> </CENTER>
  <TABLE cellSpacing=3D0 align=3Dcenter border=3D2>
    <TBODY>
    <TR>
      <TD vAlign=3Dtop>
        <TABLE cellSpacing=3D0 cellPadding=3D5 border=3D0>
          <TBODY>
          <TR>
            <TD vAlign=3Dtop width=3D200>The battery in the circuit has =
an=20
              internal resistance r and an emf E. The resistance of the =
ammeter=20
              and the conductors is negligible and the voltmeter has a =
high=20
              resistance</TD>
            <TD><IMG height=3D208 alt=3D""=20
              src=3D"http://larose/quiz/pmcelecC08.gif" =
width=3D230=20
              =
border=3D0></TD></TR></TBODY></TABLE></TD></TR></TBODY></TABLE>
  <P><!frage9><B><FONT color=3Dred>9.)</FONT> When the switch S is =
closed, the =85=20
  </B>
  <UL>
    <TABLE cellSpacing=3D0 border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50>&nbsp;</TD>
        <TD align=3Dmiddle><B>&nbsp;&nbsp;&nbsp;voltmeter=20
          reading&nbsp;&nbsp;&nbsp;</B></TD>
        <TD align=3Dmiddle><B>&nbsp;&nbsp;&nbsp;ammeter=20
          reading&nbsp;&nbsp;&nbsp;</B></TD></TR>
      <TR>
        <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD align=3Dmiddle>decreases</TD>
        <TD align=3Dmiddle>decreases</TD></TR>
      <TR>
        <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ9></TD>
        <TD align=3Dmiddle>decreases</TD>
        <TD align=3Dmiddle>increases</TD></TR>
      <TR>
        <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>decreases</TD></TR>
      <TR>
        <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ9></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>increases</TD></TR></TBODY></TABLE><!-- =
<input type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("Correct answer is option 3 (see also question =
7): 1/3 of total p.d. will be across single resistor R and 2/3 of total =
p.d. will be measured across resistors R in parallel. <br>2/3 &middot; =
12V =3D 8V; <br>and <br>1/3 &middot; 12V =3D 4V across R in =
parallel.")'>
 -->
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
  </UL>
  <P><!frage10><B><FONT color=3Dred>10.)</FONT> When the switch S is =
closed the=20
  power in the resistors R<SUB>1</SUB> and R<SUB>2</SUB> =85 </B>
  <UL>
    <TABLE cellSpacing=3D0 border=3D0>
      <TBODY>
      <TR>
        <TD width=3D50>&nbsp;</TD>
        <TD align=3Dmiddle>&nbsp;&nbsp;&nbsp;<B>power in=20
          R<SUB>1</SUB></B>&nbsp;&nbsp;&nbsp;</TD>
        <TD align=3Dmiddle>&nbsp;&nbsp;&nbsp;<B>power in=20
          R<SUB>2</SUB></B>&nbsp;&nbsp;&nbsp;</TD></TR>
      <TR>
        <TD width=3D50><B>1</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD align=3Dmiddle>decreases</TD>
        <TD align=3Dmiddle>decreases</TD></TR>
      <TR>
        <TD width=3D50><B>2</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD align=3Dmiddle>decreases</TD>
        <TD align=3Dmiddle>increases</TD></TR>
      <TR>
        <TD width=3D50><B>3</B>&nbsp;<INPUT type=3Dradio value=3D1 =
name=3DQ10></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>decreases</TD></TR>
      <TR>
        <TD width=3D50><B>4</B>&nbsp;<INPUT type=3Dradio value=3D0 =
name=3DQ10></TD>
        <TD align=3Dmiddle>increases</TD>
        <TD align=3Dmiddle>increases</TD></TR></TBODY></TABLE><!-- =
<input type=3D"button" value=3D"Explanation" =
onclick=3D'gibfeedback("Total internal resistance =3D 6 &middot; =
0,2&Omega; =3D 1,2&Omega;<br>Voltage =3D 9V<br> I =3D V/R =3D 9/1,2 =3D =
7,5A.")'>
 -->
    <SCRIPT language=3DJavaScript>zaehle()</SCRIPT>
  </UL>
  <HR color=3Dblue SIZE=3D5>

  <CENTER>
  <TABLE cellSpacing=3D0 cols=3D1 width=3D"60%" border=3D1>
    <CAPTION><B>Results</B></CAPTION>
    <TBODY>
    <TR>
      <TD>
        <CENTER><INPUT type=3Dhidden value=3Dfalse =
name=3Dbearbeitet><INPUT onclick=3Dshow() type=3Dbutton value=3D"See =
your results" name=3DButton></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><TEXTAREA name=3Dergebnis rows=3D3 readOnly =
cols=3D50></TEXTAREA></CENTER></TD></TR>
    <TR>
      <TD>
        <CENTER><INPUT onclick=3Dshowcorrect() type=3Dbutton =
value=3D"What are the correct answers?" =
name=3DButton></CENTER></TD></TR></TBODY></TABLE></CENTER></FORM>
<HR color=3Dblue SIZE=3D5>
</BLOCKQUOTE></BODY></HTML>

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